Express the result of the following calculations to the appropriate number of siginficant figures:
943 space cross times space 0.00345 space plus space 101


943 × 0·00345 + 101
= 3·25335 + 101
= 3·25 + 101 (Applying the rule of product)
= 104·25
= 104 (Applying the rule of addition)

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Express the result of the following calculations to the appropriate number of siginficant figures:
0.58 plus 324.65


0·58 + 325·65 = 324·23 (Actual result)
While carrying out addition of a number of terms, the result should be reported to the same number of decimal places as that of the term with the least number of decimal places. In the present case, both the given numbers have two decimal places, therefore, the reported sum should be only two decimal places after rounding off.
∴  Correct sum = 325·23

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Express the result of the following calculations to the appropriate number of siginficant figures:
fraction numerator 3.24 space cross times space 0.08666 over denominator 5.006 end fraction




As the number of significant-figures in the least precise factor is three (viz 3.24), therefore, the reported result after rounding off is 0·0561 (containing only three significant figures).

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Calculate the area of a rectangle whose length is 6.00 m and breadth 5.2 m. Express the result to a proper number of significant figures.


Area of rectangle = Length × Breadth = 6·00 m × 5·2 m = 31·200 m2
As the number of significant figures in the least precise factor is two, therefore, the correct answer is 31m2.

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The population of India according to 1981 census figure was 68.4 crores. Express it in scientific notation.


68·4 crores = 6·84 ×108
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