Why is aniline weaker base than cyclohexylamine?

In aniline (C6H5NH2), the phenyl group (C6H5) is an electron withdrawing group and therefore decreases electron availability on the nitrogen of - NH2 group and thus makes it a weaker base. In cyclohexylamine, the cyclohexyl group (non-aromatic) is an electron releasing group and thus increases electron density on the nitrogen of - NH2 group and makes it a stronger base than aniline (Inductive effect).



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Write structure and IUPAC name of the amide produced by the Hoffmann degradation of benzamide.


Benzamide is an aromatic amide containing seven carbon atoms. Hence, the amine formed from benzamide is aromatic primary amine containing six carbon atoms.


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How will you make the following conversions?
Ethanoic acid to Diethylamine.


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Write the chemical equations for the following conversions:
C6H5H2Cl into C6H5CH2CH2NH2


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Write structure and IUPAC name of the amide which gives propanamine by Hoffmann bromamide reaction.


Propanamine contains three carbons. Hence, the amide molecule must contain four carbons. Structure and IUPAC name of the starting amide with four carbon atoms is given below:


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