Let the radius of the bigger circle be R cm. and radii of two smaller circles are r1and r2, then according to question.
2Ï€R = 2Ï€r1Â + 2Ï€r2
⇒    2πR = 2π (19) + 2π (9)
⇒    2πR = 2π (19 + 9)
⇒    R = 28
Hence, radius of the circle be 28 cm.
We have,
r = Radius of the region representing Gold score = 10.5 cm
∴ r1 = Radius of the region representing Gold and Red scoring areas = (10.5 + 10.5) cm = 21 cm = 2r cm
r2Â = Radius of the region representing Gold, Red and Blue scoring areas = (21 + 10.5) cm = 31.5 cm = 3r cm
r3Â = Radius of the region representing Gold, Red, Blue and Black scoring areas = (31.5 + 10.5) cm = 42 cm = 4r cm
r4Â = Radius of the region representing Gold, Red, Blue, Black and white scoring areas = (42 + 10.5) cm = 52.5 cm = 5r cm
Now, A, = Area of the region representing Gold scoring area
Tick the correct answer in the following: If the perimeter and the area of a circle are numerically equal, then the radius of the circle is
(A) 2 units    (D) π units
(C) 4 units    (D) 7 units.
Let r be the radius of the circle then,
Perimeter = 2 πr
and Area = πr2
It is given that
Perimeter of circle = Area of circle
⇒ 2πr = πr2
⇒    r = 2 units
Hence, right option be (A): 2 units.
Let the radius of the required circle be R and radii of two given circles be r1Â and r2, then according to question.
πR2 = πr12 + πr22
⇒    πR2 = (r12 + r22)
⇒    R2 = 64 + 36
⇒    R2 = 100
⇒    R = 10 cm.