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Define interatomic forces and give an example?


The force between atoms of the molecule is called interatomic force.

E.g.The nucleus and electron cloud of a molecule is binded by electrostatic force. 
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Determine the volume contraction of a solid copper cube, 10 cm on an edge, when subjected to a hydraulic pressure of 7.0 ×106 Pa.

Length of an edge of the solid copper cube, l = 10 cm = 0.1 m

Hydraulic pressure, p = 7.0 × 106 Pa

Bulk modulus of copper, B = 140 × 109 Pa

Formula is given by, 

Bulk space modulus comma space straight B space equals space fraction numerator straight p over denominator open parentheses begin display style bevelled fraction numerator increment straight V over denominator straight V end fraction end style close parentheses end fraction

where comma space
fraction numerator increment straight V over denominator straight V end fraction equals space Volumetric space strain
increment straight V space equals space change space in space volume space equals space pV over straight B
straight V space equals space original space volume

Original space volume space of space the space cube comma space straight V space equals space straight l cubed

therefore space increment straight V space equals space pl cubed over straight B
space space space space space space space space space space space space equals fraction numerator space 7 space cross times space 10 to the power of 6 space cross times space left parenthesis 0.1 right parenthesis cubed space over denominator left parenthesis 140 cross times 10 to the power of 9 right parenthesis end fraction
space space space space space space space space space space space space equals space 5 space cross times space 10 to the power of negative 8 end exponent space straight m cubed

space space space space space space space space space space space space equals space 5 space cross times space 10 to the power of negative 2 end exponent space cm to the power of negative 3 end exponent space

Therefore comma space space the space volume space contraction space of space the space
solid space copper space cube space is space 5 space cross times space 10 to the power of – 2 end exponent space cm to the power of – 3 end exponent.

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How much should the pressure on a litre of water be changed to compress it by 0.10%?

Volume of water, = 1 L

It is given that water is to be compressed by 0.10%.

Therefore,

Fractional change, 
V / V = 0.1 / (100 × 1)  =  10-3

Bulk modulus, B = ρ / (V/V

rightwards double arrow              ρ = B × (V/V)
Bulk modulus of water, B = 2.2 × 109 Nm-2

                              ρ = 2.2 × 109 × 10-3  =  2.2 × 106 Nm-2 

Therefore, the pressure on water should be 2.2 ×106 Nm–2
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Compute the fractional change in volume of a glass slab, when subjected to a hydraulic pressure of 10 atm.

Hydraulic pressure exerted on the glass slab, = 10 atm = 10 × 1.013 × 105 Pa

Bulk modulus of glass, B = 37 × 109 Nm–2

Bulk modulus, B =fraction numerator straight p over denominator begin display style bevelled fraction numerator increment straight V over denominator straight V end fraction end style end fraction

where, 

V/V = Fractional change in volume

∴ V/V = p / B

          =fraction numerator space 10 space cross times space 1.013 space cross times space 10 to the power of 5 over denominator left parenthesis 37 space cross times space 10 to the power of 9 right parenthesis end fraction
          = 2.73 × 10-5 

Hence, the fractional change in the volume of the glass slab is 2.73 × 10–5.
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Anvils made of single crystals of diamond, with the shape as shown in Fig. 9.14, are used to investigate behaviour of materials under very high pressures. Flat faces at the narrow end of the anvil have a diameter of 0.50 mm, and the wide ends are subjected to a compressional force of 50,000 N. What is the pressure at the tip of the anvil?


Diameter of the cones at the narrow ends, d = 0.50 mm = 0.5 × 10–3 m

Radius, r = d/2  =  0.25 × 10-3 m 

Compressional force, F = 50000 N\

Pressure at the tip of the anvil is given by, 


straight P space space equals space straight F over straight A equals space fraction numerator 50000 over denominator straight pi space left parenthesis 0.25 cross times 10 to the power of negative 3 end exponent right parenthesis squared end fraction space

space space space space equals space 2.55 cross times 10 to the power of 11 space Pa space

Therefore, the pressure at the tip of the anvil is 2.55 × 1011Pa. 
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