zigya tab
Advertisement

Find the area of the region bounded by the curve y= x and the lines x = 1, x = 4 and the x-axis in the first quadrant.


The equation of curve is y2 = x
Required area = integral subscript 1 superscript 4 space straight y space dx space equals space integral subscript 1 superscript 4 square root of straight x space end root dx space equals integral subscript 1 superscript 4 straight x to the power of 1 half end exponent dx
                        equals space open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 1 superscript 4 space equals 2 over 3 open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript 1 superscript 4 space equals space 2 over 3 open square brackets open parentheses 4 close parentheses to the power of 3 over 2 end exponent minus 1 close square brackets
equals space 2 over 3 left parenthesis 8 minus 1 right parenthesis space equals space 2 over 3 cross times 7 space equals space 14 over 3 sq. space units.


 
953 Views

Advertisement
The area between x = y2 and x = 4 is divided into two equal parts by the line x = a, find the value of a.

The equation of parabola is y2 = x
From the given condition, area OAP under y2 = x between x = 0 and x = a = area ABQP under y2 = x between x = a and x = 4.
therefore space space space integral subscript 0 superscript straight a straight y space dx space equals space integral subscript straight a superscript 4 space straight y space dx
rightwards double arrow space space integral subscript 0 superscript straight a square root of straight x space dx space equals space integral subscript straight a superscript 4 square root of straight x space dx
rightwards double arrow space space integral subscript 0 superscript straight a straight x to the power of 1 half end exponent dx space equals space integral subscript straight a superscript 4 straight x to the power of 1 half end exponent dx
rightwards double arrow space space open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 0 superscript straight a space equals open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript straight a superscript 4 space space space space space space space space space space space space space space space space space space space space space space space space rightwards double arrow space space space space space space open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript 0 superscript straight a space equals space open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript straight a superscript 4
rightwards double arrow space space space space straight a to the power of 3 over 2 end exponent minus 0 space equals space 4 to the power of 3 over 2 end exponent minus straight a to the power of 3 over 2 end exponent space space space space space space space space space space space space space space space space space space space space space space space rightwards double arrow space space 2 space straight a to the power of 3 over 2 end exponent space equals space 8 space space space rightwards double arrow space space straight a to the power of 3 over 2 end exponent space equals space 4 space space space space rightwards double arrow space space straight a space space equals 4 to the power of 4 over 3 end exponent

741 Views

Find the area of the region bounded by the curve y2 = 4x and the line x = 3.


The equation of parabola is
y2 = 4 x
The equation of line is
x = 3
Also, we know that parabola is symmetric about x-axis
∴ required area = 2 (area ORPO)

equals space 2 integral subscript 0 superscript 3 2 square root of straight x space dx space equals space 4 space integral subscript 0 superscript 3 straight x to the power of 1 half end exponent dx
equals space 4 open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 0 superscript 3 space equals space 8 over 3 open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript 0 superscript 3 space equals space 8 over 3 open parentheses 3 to the power of 3 over 2 end exponent minus 0 close parentheses space equals space 8 over 3 cross times square root of 27
equals space 8 over 3 cross times 3 square root of 3 space equals space 8 square root of 3 space sq. space units.

341 Views

Find the area of the region bounded by x2 = 4 y, y = 2, y = 4 and the y-axis in the first quadrant.


The equation of curve is x2 = 4y, which is an upward parabola.
Lines are y = 2 and y  = 4
Required area  = Area ABCD
                        equals space integral subscript 2 superscript 4 straight x space dy space equals space integral subscript 2 superscript 4 2 square root of straight y space dy
equals space 2 integral subscript 2 superscript 4 straight y to the power of 1 half end exponent dy space equals space 2 open square brackets fraction numerator straight y to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 2 superscript 4
equals space 4 over 3 open square brackets straight y to the power of 3 over 2 end exponent close square brackets subscript 2 superscript 4 space equals space 4 over 3 open square brackets left parenthesis 4 right parenthesis to the power of 3 over 2 end exponent minus left parenthesis 2 right parenthesis to the power of 3 over 2 end exponent close square brackets
equals space 4 over 3 left parenthesis 8 minus 2 square root of 2 right parenthesis space equals space fraction numerator 32 minus 8 square root of 2 over denominator 3 end fraction sq. space units



 

275 Views

Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.

The equation of curve is y2 = 9x, which is right handed parabola.
Two lines are x = 2,  x = 4.
    Required area = Area ABCD
                            equals space integral subscript 2 superscript 4 straight y space dx space equals space integral subscript 2 superscript 4 3 square root of straight x space dx space equals space 3 space integral subscript 2 superscript 4 straight x to the power of 1 half end exponent dx
space equals space 3 open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 2 superscript 4 space equals space 3 cross times 2 over 3 open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript 2 superscript 4
equals space 2. space open square brackets left parenthesis 4 right parenthesis to the power of 3 over 2 end exponent minus left parenthesis 2 right parenthesis to the power of 3 over 2 end exponent close square brackets space equals space 2 space left square bracket space 8 space minus square root of 8 right square bracket space equals space 2 left parenthesis 8 minus 2 square root of 2 right parenthesis
equals space left parenthesis 16 minus 4 square root of 2 right parenthesis space sq. space units.


752 Views

Advertisement