Find the multiplicative inverse of the following.(i) 2–4  �
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Simplify and write in exponential form.
p3 x p–10


p3 x p–10= left parenthesis straight p right parenthesis to the power of 3. space left parenthesis negative 10 right parenthesis end exponent space equals left parenthesis straight p right parenthesis to the power of negative 7 end exponent or space fraction numerator 1 over denominator left parenthesis 10 right parenthesis to the power of 7 end fraction

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Evaluate:
3 to the power of negative 2 end exponent

3 to the power of negative 2 end exponent equals 1 over 3 squared equals fraction numerator 1 over denominator 3 cross times 3 end fraction equals 1 over 9
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Find the multiplicative inverse of the following.
(i) 2–4            (ii) 10–5         (iii) 7–2    (iv) 5–3   (v) 10–100


(i) The multiplicative inverse of 2–4 is 24.

(ii) The multiplicative inverse of 10–5 is 105

(iii) The multiplicative inverse of 7–2 is 72.

(iv) The multiplicative inverse of 5–3 is 53.

(v) The multiplicative inverse of 10–100 is 10100.

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Simplify and write in exponential form.
(–2)–3 x (–2)–4


(–2)–3 x (–2)–4  = (-2)(-3) + (-4)                  [∵ space space straight a to the power of straight m cross times straight a to the power of straight n equals straight a to the power of straight m plus straight n end exponent]
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#6 {main}</pre> or  fraction numerator 1 over denominator left parenthesis negative 2 right parenthesis to the power of 7 end fraction

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Simplify and write in exponential form.
32 x 3–5 x 36


32 x 3–5 x 36 = 3 to the power of 2 plus left parenthesis negative 5 right parenthesis plus 6 end exponent space equals space 3 to the power of 8 minus 5 end exponent equals 3 cubed

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