Chapter Chosen

ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

Book Chosen

ગણિત ધોરણ 11 સેમિસ્ટર 2

Subject Chosen

ગણિત

Book Store

Download books and chapters from book store.
Currently only available for
CBSE Gujarat Board Haryana Board

Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for
Class 10 Class 12

ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space straight theta space plus space sec space straight theta space equals space 3$

નીચેનું સમીકરણ ઉકેલો :
$sin space 2 theta space plus space cos space theta space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos squared space straight theta space plus space square root of 3 space cos space straight theta space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space 2 straight theta space plus space square root of 2 space equals space 0$

therefore space cos space 2 straight theta space equals space minus fraction numerator 1 over denominator square root of 2 end fraction space equals space cos space open parentheses straight pi space minus space straight pi over 4 close parentheses space equals space cos space open parentheses fraction numerator 3 straight pi over denominator 4 end fraction close parentheses therefore space cos space 2 straight theta space equals space cos space open parentheses fraction numerator 3 straight pi over denominator 4 end fraction close parentheses therefore space 2 straight theta space equals space 2 kπ space plus-or-minus space fraction numerator 3 straight pi over denominator 4 end fraction comma space straight k space element of space straight Z therefore space straight theta space equals space kπ space plus-or-minus space fraction numerator 3 straight pi over denominator 8 end fraction space comma space straight k space element of space straight Z therefore space ઉક ે લગણ space colon space open curly brackets kπ space plus-or-minus space fraction numerator 3 straight pi over denominator 8 end fraction space left enclose space straight k space element of space straight z end enclose close curly brackets

નીચેનું સમીકરણ ઉકેલો :
$4 space sin squared space straight theta space minus space 8 space cos space straight theta space plus space 1 space equals space 0$

Switch