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ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

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ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

નીચેનું સમીકરણ ઉકેલો :
$2 space cos squared space straight theta space plus space square root of 3 space cos space straight theta space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space straight theta space plus space sec space straight theta space equals space 3$

નીચેનું સમીકરણ ઉકેલો :
$sin space 2 theta space plus space cos space theta space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space 2 straight theta space plus space square root of 2 space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$4 space sin squared space straight theta space minus space 8 space cos space straight theta space plus space 1 space equals space 0$

therefore space 4 space minus space 4 space cos squared space straight theta space minus space 8 space cos space straight theta space plus space 1 space equals space 0 therefore space 4 space cos squared space straight theta space plus space 8 space cos space straight theta space minus space 5 space equals space 0 therefore space 4 space cos squared space straight theta space plus space 10 space cos space straight theta space minus space 2 space cos space straight theta space minus space 5 space equals space 0 therefore space 2 space cos space straight theta space open parentheses 2 space cos space straight theta space plus space 5 close parentheses space minus space 1 space open parentheses 2 space cos space straight theta space plus space 5 close parentheses space equals space 0 therefore space open parentheses 2 space cos space straight theta space minus space 1 close parentheses space open parentheses 2 space cos space straight theta space plus space 5 close parentheses space equals space 0 therefore space cos space straight theta space equals space 1 half space અથવ ા space cos space straight theta space equals space minus 5 over 2

પરંતુ $cos space theta space equals space minus 5 over 2 space less than space minus 1$ , જે શક્ય નથી.

હવે, $cos space theta space equals space 1 half$

$therefore space cos space straight theta space equals space 1 half space equals space cos space straight pi over 3 therefore space straight theta space equals space 2 kπ space plus-or-minus space straight pi over 3 space comma space straight k space element of space straight Z therefore space ઉક ે લગણ space colon bold space open curly brackets bold 2 bold kπ bold space bold plus-or-minus bold space bold pi over bold 3 bold space left enclose bold space bold k bold space bold element of bold space bold Z end enclose close curly brackets$

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ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

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