Chapter Chosen

ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

Book Chosen

ગણિત ધોરણ 11 સેમિસ્ટર 2

Subject Chosen

ગણિત

Book Store

Download books and chapters from book store.
Currently only available for
CBSE Gujarat Board Haryana Board

Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for
Class 10 Class 12

ત્રિકોણમિતીય સમીકરણો અને ત્રિકોણના ગુણધર્મો

નીચેનું સમીકરણ ઉકેલો :
$sin space 2 theta space plus space cos space theta space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space straight theta space plus space sec space straight theta space equals space 3$

therefore space 2 space cos space straight theta space plus space fraction numerator 1 over denominator cos space straight theta space end fraction space equals space 3 therefore space 2 space cos squared space straight theta space minus space 3 space cos space straight theta space plus space 1 space equals space 0 therefore space 2 space cos squared space straight theta space minus space 2 space cos space straight theta space minus space cos space space straight theta space plus space 1 space equals space 0 therefore space open parentheses 2 space cos space straight theta space minus space 1 close parentheses space open parentheses cos space straight theta space minus space 1 close parentheses space equals space 0 therefore space 2 space cos space straight theta space minus space 1 space equals space 0 space અથવ ા space cos space straight theta space minus space 1 space equals space 0 therefore space cos space straight theta space equals space 1 half space અથવ ા space cos space straight theta space equals space 1 therefore space cos space straight theta space equals space 1 half space equals space cos space straight pi over 3 space અથવ ા space cos space straight theta space equals space 1 space equals space cos space 0 therefore space straight theta space equals space 2 kπ space plus-or-minus space straight pi over 3 space comma space straight k space element of space straight Z space અથવ ા space straight theta space equals space 2 kπ space plus-or-minus space 0 space comma space straight k space element of space straight Z therefore space straight theta space equals space 2 kπ space comma space straight k space element of space straight Z space અથવ ા space straight theta space equals space 2 kπ space plus-or-minus space straight pi over 3 space comma space straight k space element of space straight Z therefore space ઉક ે લગણ space colon space open curly brackets bold 2 bold kπ bold space left enclose bold space bold k bold space bold element of bold space bold Z end enclose close curly brackets bold space bold union bold space open curly brackets bold 2 bold kπ bold space bold plus-or-minus bold space bold pi over bold 3 bold space left enclose bold space bold k bold space bold element of bold space bold Z end enclose close curly brackets

નીચેનું સમીકરણ ઉકેલો :
$2 space cos space 2 straight theta space plus space square root of 2 space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$4 space sin squared space straight theta space minus space 8 space cos space straight theta space plus space 1 space equals space 0$

નીચેનું સમીકરણ ઉકેલો :
$2 space cos squared space straight theta space plus space square root of 3 space cos space straight theta space equals space 0$

Switch