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ગણિત ધોરણ 11 સેમિસ્ટર 2

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વિકલન

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :
$1 over straight x space semicolon space x space equals space 1$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$3 straight x squared space minus space 2 straight x space plus space 1 space semicolon space straight x space equals space minus 1 space$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :
sin x ; x = 0 આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$cos space x space semicolon space x space equals space straight pi over 2$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$fraction numerator 3 straight x space plus space 2 over denominator 2 straight x space plus space 3 end fraction space semicolon space x space equals space 1$ આગળ

bold અહ ીં bold comma space straight f space left parenthesis straight x right parenthesis space equals space fraction numerator 3 straight x space plus space 2 over denominator 2 straight x space plus space 3 end fraction bold હવ ે comma space straight x space equals space 1 space bold આગળ bold space bold f bold space bold ન ો bold space bold વ િ કલ િ ત bold comma straight f apostrophe left parenthesis 1 right parenthesis space equals space limit as straight h rightwards arrow 0 of space space fraction numerator straight f space left parenthesis 1 space plus space straight h space right parenthesis space minus space straight f space left parenthesis 1 right parenthesis over denominator straight h end fraction

equals space limit as straight h rightwards arrow 0 of space fraction numerator begin display style fraction numerator 3 open parentheses 1 space plus space straight h close parentheses space plus space 2 over denominator 2 space open parentheses 1 space plus space straight h close parentheses space plus space 3 end fraction end style space minus space begin display style fraction numerator 3 space left parenthesis 1 right parenthesis space plus space 2 over denominator 2 space left parenthesis 1 right parenthesis space plus space 3 end fraction end style over denominator straight h end fraction equals space limit as straight h rightwards arrow 0 of space fraction numerator begin display style fraction numerator 5 space plus space 3 straight h over denominator 5 space plus space 2 straight h end fraction end style space minus space 1 over denominator straight h end fraction equals space limit as straight h rightwards arrow 0 of space fraction numerator 5 space plus space 3 straight h space minus space 5 space minus space 2 straight h over denominator straight h space open parentheses 5 space plus space 2 straight h close parentheses end fraction equals space limit as straight h rightwards arrow 0 of space space fraction numerator straight h over denominator straight h space open parentheses 5 space plus space 2 straight h close parentheses end fraction equals space limit as straight h rightwards arrow 0 of space fraction numerator 1 over denominator 5 space plus space 2 straight h end fraction equals space fraction numerator 1 over denominator 5 space plus space 0 end fraction equals space bold 1 over bold 5

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