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વિકલન

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :
$1 over straight x space semicolon space x space equals space 1$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$cos space x space semicolon space x space equals space straight pi over 2$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$3 straight x squared space minus space 2 straight x space plus space 1 space semicolon space straight x space equals space minus 1 space$ આગળ

અહીં, $straight f space left parenthesis straight x right parenthesis space equals space 3 straight x squared space minus space 2 straight x space plus space 1$

હવે, x = -1 આગળ f નો વિકલિત,

$straight f apostrophe space open parentheses negative 1 close parentheses space equals space limit as straight h rightwards arrow 0 of space space fraction numerator straight f space open parentheses negative 1 space plus space straight h close parentheses space minus space straight f space open parentheses negative 1 close parentheses over denominator straight h end fraction$

$equals space limit as straight h rightwards arrow 0 of space space fraction numerator open parentheses 3 open parentheses negative 1 space plus space straight h close parentheses squared space minus space 2 space open parentheses negative 1 space plus space straight h close parentheses space plus space 1 close parentheses space minus space open parentheses 3 open parentheses negative 1 close parentheses squared space minus space 2 space open parentheses negative 1 close parentheses plus space 1 close parentheses over denominator straight h end fraction equals space limit as straight h rightwards arrow 0 of space fraction numerator open parentheses 3 open parentheses 1 space minus space 2 straight h space plus space straight h squared space close parentheses space plus space 2 space minus space 2 straight h space plus space 1 close parentheses space minus space open parentheses 3 space plus space 2 space plus space 1 close parentheses over denominator straight h end fraction equals space limit as straight h rightwards arrow 0 of space fraction numerator 3 space minus space 6 straight h space plus space 3 straight h squared space plus space 3 space minus space 2 straight h space minus space 6 over denominator straight h end fraction equals space limit as straight h rightwards arrow 0 of space space fraction numerator 3 straight h squared space minus space 8 straight h over denominator straight h end fraction equals space limit as straight h rightwards arrow 0 of space space open parentheses 3 straight h space minus space 8 close parentheses equals space 0 space minus 8 equals space bold minus bold space bold 8$

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :

$fraction numerator 3 straight x space plus space 2 over denominator 2 straight x space plus space 3 end fraction space semicolon space x space equals space 1$ આગળ

વ્યાખ્યાની મદદથી નીચેના વિધેયના આપેલ બિંદુએ વિકલિત શોધો :
sin x ; x = 0 આગળ

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