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Class 10 Class 12

સમીકરણ

નીચેનું સમીકરણ ઉકેલો :
$fraction numerator bold 2 bold x over denominator bold 3 end fraction bold space bold plus bold space bold 1 bold space bold equals bold space fraction numerator bold 7 bold x over denominator bold 15 end fraction bold space bold plus bold space bold 3$

નીચેનું સમીકરણ ઉકેલો :
$bold x over bold 2 bold space bold minus bold space bold 2 bold space bold equals bold space bold x over bold 3 bold space bold plus bold space bold 1$

નીચેનું સમીકરણ ઉકેલો :
$bold x bold space bold equals bold space bold 4 over bold 5 bold space open parentheses bold x bold space bold plus bold space bold 10 close parentheses$

નીચેનું સમીકરણ ઉકેલો :
3x + 8 = -5x + 4

bold therefore bold space bold 3 bold x bold space bold plus bold space bold 8 bold space bold plus bold space bold 5 bold x bold space bold equals bold space bold 4 bold therefore bold space bold 8 bold x bold space bold plus bold space bold 8 bold space bold equals bold space bold 4 bold therefore bold space bold 8 bold x bold space bold equals bold space bold 4 bold space bold minus bold space bold 8 bold therefore bold space bold 8 bold x bold space bold equals bold space bold minus bold 4 bold therefore bold space bold x bold space bold equals bold space fraction numerator bold minus bold 4 over denominator bold 8 end fraction bold therefore bold space bold x bold space bold equals bold space open parentheses bold minus bold 1 over bold 2 close parentheses

નીચેનું સમીકરણ ઉકેલો :
$bold 5 bold x bold space bold plus bold space bold 7 over bold 2 bold space bold equals bold space fraction numerator bold 3 bold x over denominator bold 2 end fraction bold space bold minus bold space bold 14$

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