Subject

Physics

Class

ICSE Class 10

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

1.

With reference to the terms mechanical advantage, velocity ratio and efficiency of a machine, name the term that will not change for a machine of a given design.

ii) Define the term stated by you in part (i). 


i) Velocity Ratio.

ii) Velocity Ratio is the ratio of velocity of effort to the velocity of load. 

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2.

State the conditions required for total internal reflection of light to take place.


The conditions for total internal reflection to take place are: 

i) Light must always go from a denser to a rarer medium.

ii) The angle of incidence must be more than the critical angle. 

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3.

Copy and complete the following table:

Types of lens

Position of object

Nature of image

Size of image

Convex

At F

 

 

concave

At infinity

 

 


Types of lens

Position of object

Nature of image

Size of image

Convex

At F

Real and Inverted

Highly magnified

concave

At infinity

Virtual and erect

Higly diminished

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4.

What is the SI unit of energy? How is the electron volt (eV) related to it? 


Joule (J) is the SI unit of energy. 

1 eV = 1.6 × 10-19

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5.

State the energy changes that takes place in the following when they are in use:

i) a photovoltaic cell

ii) an electromagnet


i) Light energy to electrical energy.

ii) Electrical energy to mechanical energy

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6.

A ray of light strikes the surface of a rectangular glass block such that the angle of incidence is i) 0o ii) 420. Sketch a diagram to show the approximate the path taken by the ray in each case as it passes through the glass block and emerges from it. 


We know that angle of incidence = angle of reflection. 

i) Given: i = 0o

   Therefore, r = 0 


ii) 

Given: I = 42o

Therefore, r = 42o

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7.

i) Why is white light considered to be polychromatic in nature?

ii) Give the range of the wavelength of those electromagnetic waves which are visible to us.

i) White light is considered to be polychromatic in nature because it contains number of wavelengths ( 4000 straight A with straight o on top– 8000straight A with straight o on top ) and there are seven colors in it (VIBGYOR).

ii) 4000 straight A with straight o on top – 8000 straight A with straight o on top

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8.

i) Copy and complete the diagram to show the formation of the image of the object AB.

ii) What is the name given to X. 


i)

 

ii) X is focus or the principal focus. 
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9.

6.5 kJ of energy causes a displacement of 64 m in a body in the direction of force in 2.5 seconds. Calculate:

i) the force applied

ii) power in horse power(hp)

[ Take 1 hp = 764 W]


Given:

E = 6.4 kJ = 6400 J

D = 64 m

T = 2.5 sec

i) Force space equals space Energy over Displacement space equals space 6400 over 64 space equals space 100 space straight N 
ii) Let,

Error converting from MathML to accessible text.

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10.

A body of mass 5 kg is moving with a velocity of 10 m/s. What will be the ratio of its initial kinetic energy and final kinetic energy, if the mass of the body is doubled and its velocity is halved? 


K. E subscript 1 space equals space 1 half space m v squared space
italic space italic space italic space italic space italic space italic space italic space italic space equals space 1 half space cross times space 5 space cross times space left parenthesis 10 right parenthesis squared space

italic space italic space italic space italic space italic space italic space italic space italic space italic space equals 1 half cross times 500 space equals space 250 space J

K. E subscript italic 2 space equals space italic 1 over italic 2 space m v to the power of italic 2 space
italic space italic space italic space italic space italic space italic space italic space italic space equals space italic 1 over italic 2 space cross times space 10 space cross times space left parenthesis 5 italic right parenthesis to the power of italic 2 space

italic space italic space italic space italic space italic space italic space italic space italic space equals space 5 space straight x space 25 space equals space 125 space straight J

fraction numerator K. E subscript 1 over denominator K. E subscript 2 end fraction space equals space 250 over 125 space equals 2 over 1   
Initial kinetic energy will become twice of the final kinetic energy. 
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