I > 2/ 3 and J > 2
I < 2/ 3 and J < 2
I < 2/ 3 and J > 2
I < 2/ 3 and J > 2
The area of the plane region bounded by the curves x + 2y2= 0 and x + 3y2= 1 is equal to
5/3
1/3
2/3
2/3
D.
2/3
Solving the equations we get the points of intersection (–2, 1) and (–2, 1)The bounded region is shown as shaded region