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    Subject
    Mathematics

    Class

    JEE Class 12

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    JEE Mathematics Solved Question Paper 2008

    Multiple Choice QuestionsMultiple Choice Questions

    31.

    How many real solutions does the equation x7+ 14x5+ 16x3+ 30x – 560 = 0 have?

    • 7

    • 1

    • 3

    • 3

    149 Views
    Answer
    32. Let space straight I space space equals space integral subscript 0 superscript 1 space fraction numerator sin space straight x over denominator square root of straight x end fraction dx space and space straight J space equals space integral subscript 0 superscript 1 space fraction numerator cos space straight x over denominator square root of straight x end fraction space dx then which one is true?

    • I > 2/ 3 and J > 2

    • I < 2/ 3 and J < 2

    • I < 2/ 3 and J > 2

    • I < 2/ 3 and J > 2

    100 Views
    Answer
    33.

    The area of the plane region bounded by the curves x + 2y2= 0 and x + 3y2= 1 is equal to 

    • 5/3

    • 1/3

    • 2/3

    • 2/3

    163 Views
    Answer
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    34.

    The value of square root of 2 space integral fraction numerator sin space straight x space dx over denominator sin space open parentheses straight x minus begin display style straight pi over 4 end style close parentheses end fraction space is

    • space straight x plus space log open vertical bar cos space open parentheses straight x minus straight pi over 4 close parentheses close vertical bar space plus space straight C
    • straight x space minus log space open vertical bar sin space open parentheses straight x minus straight pi over 4 close parentheses close vertical bar space plus straight c
    • straight x space plus space log space open vertical bar sin space open parentheses straight x minus straight pi over 4 close parentheses close vertical bar space plus straight c
    • straight x space plus space log space open vertical bar sin space open parentheses straight x minus straight pi over 4 close parentheses close vertical bar space plus straight c

    C.

    straight x space plus space log space open vertical bar sin space open parentheses straight x minus straight pi over 4 close parentheses close vertical bar space plus straight c
    square root of 2 space integral fraction numerator sin space straight x space dx over denominator sin space open parentheses straight x minus begin display style straight pi over 4 end style close parentheses end fraction space equals space square root of 2 integral fraction numerator sin space open parentheses straight x minus begin display style straight pi over 4 end style plus begin display style straight pi over 4 end style close parentheses dx over denominator sin space open parentheses straight x minus space begin display style straight pi over 4 end style close parentheses end fraction space equals space square root of 2 space integral open parentheses cos space straight pi over 4 space plus space cot space open parentheses straight x minus space straight pi over 4 close parentheses space sin space straight pi over 4 close parentheses space dx space equals space integral space dx space plus space integral cot space open parentheses straight x space minus space straight pi over 4 close parentheses dx equals space straight x space plus space In space open vertical bar sin space open parentheses straight x minus straight pi over 4 close parentheses close vertical bar space plus straight c
    98 Views
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