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CBSE

Subject

Physics

Class

JEE Class 12

JEE Physics 2005 Exam Questions

Multiple Choice Questions

1.

The upper half of an inclined plane with inclination φ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by

  • 2sinφ

  • 2cosφ

  • 2tanφ
  • tanφ


C.

2tanφ
181 Views

2.

A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

  • 3.0 cm

  • 2.0 cm

  • 1.5 cm

  • 1.0 cm


D.

1.0 cm

straight F.3 space equals 1 half mv squared minus 1 half straight m straight v squared over 4
straight F left parenthesis 3 plus straight x right parenthesis space equals 1 half mv squared
space straight x space equals space 1 space cm
217 Views

3.

A particle is moving eastwards with a velocity of 5 m/s in 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is

  • fraction numerator 1 over denominator square root of 2 end fraction straight m divided by straight s squared spacetowards north-east
  • 1 half straight m divided by straight s squared spacetowards north.
  • zero

  • fraction numerator 1 over denominator square root of 2 end fraction straight m divided by straight s squared spacetowards north-west

D.

fraction numerator 1 over denominator square root of 2 end fraction straight m divided by straight s squared spacetowards north-west


straight a with rightwards arrow on top space equals space fraction numerator stack straight V subscript straight f with rightwards arrow on top minus stack straight V subscript straight i with rightwards arrow on top over denominator straight t end fraction space
space equals space fraction numerator 5 straight j with hat on top minus 5 straight i with hat on top over denominator 10 end fraction space equals 1 half space left parenthesis straight j with hat on top minus straight i with hat on top right parenthesis
therefore straight a space equals space fraction numerator 1 over denominator square root of 2 end fraction ms to the power of negative 2 end exponent space towards space north space west
199 Views

4.

A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then

  • S=ft

  • S= ft2/72

  • S = 1/2 ft2

  • S = 1/4 ft2


B.

S= ft2/72



straight S space equals space fraction numerator ft subscript 1 superscript 2 over denominator 2 end fraction
straight v subscript straight o space equals square root of 2 Sf end root
During space retardation
straight S subscript 2 space equals space 2 straight S
During space constant space velocity
15 straight S space minus 3 straight S space equals space 12 space straight S space equals straight v subscript straight o straight t
rightwards double arrow space straight S space equals ft squared over 72
275 Views

5.

The relation between time t and distance x is t=ax2 +bx where a and b are constants. The acceleration is

  • −2abv2

  • 2bv3

  • −2av3

  • 2av2


C.

−2av3

t = ax2 + bx by differentiating acceleration = - 2av3

268 Views

6.

A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flights in the two cases, then the product of the two time of flights is proportional to

  • R2

  • 1/R2

  • 1/R

  • R


D.

R

straight t subscript 1 straight t subscript 2 space equals space fraction numerator 2 straight u squared sin space 2 straight theta over denominator straight g squared end fraction space equals space fraction numerator 2 straight R over denominator straight g end fraction
251 Views

7.

An annular ring with inner and outer radii R1 and R2 is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring, F1/F2 is

  • R1/R2

  • (R1/R2)2

  • 1

  • R2/R1


A.

R1/R2

straight F subscript 1 over straight F subscript 2 space equals space fraction numerator straight R subscript 1 straight omega squared over denominator straight R subscript 2 straight omega squared end fraction space equals straight R subscript 1 over straight R subscript 2
298 Views

8.

Out of the following pair, which one does NOT have identical dimensions is

  • angular momentum and Planck’s constant

  • impulse and momentum

  • moment of inertia and moment of a force

  • work and torque


C.

moment of inertia and moment of a force

221 Views

9.

A smooth block is released at rest on a 45° incline and then slides a distance d. The time taken to slide is n times as much to slide on rough incline than on a smooth incline. The coefficient of friction is

  • straight mu subscript straight k space equals space 1 minus 1 over straight n squared
  • straight mu subscript straight k space equals space square root of 1 minus 1 over straight n squared end root
  • straight mu subscript straight s space equals space 1 minus 1 over straight n squared
  • straight mu subscript s space equals space square root of 1 minus 1 over straight n squared end root

A.

straight mu subscript straight k space equals space 1 minus 1 over straight n squared
straight d space equals space 1 half fraction numerator straight g over denominator square root of 2 end fraction straight t subscript 1 superscript 2
straight d equals space 1 half fraction numerator straight g over denominator square root of 2 end fraction left parenthesis 1 minus straight mu subscript straight k right parenthesis straight t subscript 2 superscript 2
fraction numerator straight t subscript 2 superscript 2 over denominator straight t subscript 1 superscript 2 end fraction space equals space straight n squared space equals fraction numerator 1 over denominator 1 minus straight mu subscript straight k end fraction
288 Views

10.

A parachutist after bailing outfalls 50 m without friction. When a parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3 m/s. At what height, did he bail out?

  • 91 m

  • 182 m

  • 293 m

  • 111 m


C.

293 m

straight s equals space 50 space plus open parentheses fraction numerator 3 squared minus left parenthesis 2 straight x 10 straight x 50 right parenthesis over denominator 2 left parenthesis negative 2 right parenthesis end fraction close parentheses
space equals space 293 space straight m
142 Views

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