Subject

Chemistry

Class

NEET Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

31.

What would be the freezing point of aqueous solution containing 17g of C2H5OH in 1000 g of water?

  • 0.34°C

  • 0.0°C

  • -0.34°C

  • -0.69°C


32.

The pH of a solution is 5.0. If H+ ion concentration is decreased 100 times. Then the solution will be :

  • neutral

  • more acidic

  • basic

  • of the same acidity


33.

Percentage of silver in the alloy German siiver is:

  • 0%

  • 1.0%

  • 2.5%

  • 1.5%


34.

Rusting of iron is a chemical reaction. The reaction is :

  • double decomposition

  • combination

  • displacement

  • analysis


Advertisement
35.

The 3rd transitional series contain elements having atomic numbers from:

  • 21 to 29

  • 21 to 30

  • 20 to 30

  • 21 to 31


36.

Which one of the following colloidal solution is positive sol?

  • Gelatin in strongly acidic solution

  • Smoke

  • Dlay soil

  • Blood


37.

How many grams of CaC2O4 will dissolve in distilled water to make one litre of saturated solution? Solubility product of CaC2O4 is 2.5 x 10-9 mol2 litre-2 and its molecular weight is 128

  • 0.0640 gm

  • 0.0032 gm

  • 0.0128 gm

  • 0.0064 gm


38.

Which of the following is coinage metal?

  • Cu

  • Sn

  • Zn

  • Pb


Advertisement
39.

Gasoline is

  • C17H36 to C21H50

  • C7H24 to C14H34

  • C7H16 to C10H22

  • C3H8 to C6H14


Advertisement

40.

In the complex [Co(en)2Cl2 ] Br, the co-ordination number and oxidation state of cobalt are

  • 6 and +1

  • 6 and +3

  • 3 and +3

  • 4 and +2


B.

6 and +3

Ethylene diamine (en) is a bidentate ligand, i.e., it has two donor centres. In the complex [CO(en)2 Cl2 ]Br, the total number of donor atoms is 6 (4 from two 'en' moles + 2 Cl- ions).

Let the oxidation state of 'Co' be x.

+ (0 × 2) + (-1 × 2) + (-1) = 0

                          x + 0 - 2 - 1 = 0

                                     x - 3 = 0

                                          x = +3


Advertisement
Advertisement