Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

21.

In the hydrocarbon

straight C with 6 below straight H subscript 3 space minus straight C with 5 below straight H equals straight C with 4 below straight H minus straight C with 3 below straight H subscript 2 minus straight C with 2 below identical to straight C with 1 below straight H

The state of hybridization of carbon 1, 3, and 5 are in the following sequence

  • sp2, sp, sp3

  • sp, sp3, sp2

  • sp, sp2, sp3

  • sp, sp2, sp3

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22.

The value of KP1 and Kp2 for the reactions

X ⇌ Y +Z  ... (i)
A ⇌ 2B    ... (ii)

are in the ratio of 9:1. if the degree of dissociation of X and A be equal, then the total pressure at equilibrium (i) and (ii) are in the ratio

  • 3:1

  • 1:9

  • 36:1

  • 36:1

428 Views

23.

The value of equilibrium constant of the reaction HI (g) ⇌ H2(g)/2 + I2/2 is 8.0
The equilibrium constant of the reaction H2(g) + I2(g) ⇌ 2 HI (g)  will be

  • 1/16

  • 1/64

  • 16

  • 16

323 Views

24.

Green chemistry means such reactions which 

  • produce colour during reactions

  • reduce the use and production of hazardous chemicals

  • are related to the depletion of the ozone layer

  • are related to the depletion of the ozone layer

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25.

The alkali metals form salt-like hydrides by the direct synthesis at elevated temperature. The thermal stability of these hydrieds decreases in which of the following orders?

  • CsH > RbH > KH > NaH >LiH

  • KH > NaH> LiH > CsH >RbH

  • NaH > LiH >KH> RbH> CsH

  • NaH > LiH >KH> RbH> CsH

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26.

The stability of carbanions in the following

1 right parenthesis space RC space identical to straight C with minus on top straight H
space 2 right parenthesis space straight C subscript 6 straight H subscript 5 to the power of minus
3 right parenthesis space straight R subscript 2 straight C space equals space straight C to the power of minus straight H
4 right parenthesis space straight R subscript 3 straight C space equals space straight C to the power of minus straight H

is in the order of 

  • (1) > (2) > (3) > (4)

  • (2) > (3) > (4) > (1)

  • (4) > (2) > (3)  > (1)

  • (4) > (2) > (3)  > (1)

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27.

On the basis of the following Eo values; the strongest oxidising agent is

[Fe(CN)6]4- → [Fe(CN)6]3-] +e- ;
Eo = -0.35 V

Fe2+ → Fe3+  +e-; E = -0.77 V

  • [Fe(CN)6]4-

  • Fe2+

  • Fe3+

  • Fe3+


C.

Fe3+

Oxidised form + ne- → Reduced Form

The substance which has lower reduction potential are stronger reducing agent while the substances which have higher reduction potential are a stronger oxidising agent.

[Fe(CN)6]3- + e- →[Fe(CN)6]4- ; Eo = 0.35 V

Fe3+ + e- → Fe2+ ;                      Eo = 0.77 V

The reduction potential of Fe3+/ Fe2+ is higher, hence, Fe3+ is a strongest oxidising agent.

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28.

Kohlrausch's law states that at

  • finite dilution, each ion makes a definite contribution to the equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.

  • infinite dilution, each ion makes a definite contribution to the equivalent conductance of an electrolyte depending on the nature of the other ion of the electrolyte.

  • infinite dilution, each ion makes a definite contribution to the conductance of an electrolyte whatever be the nature of the other ions of the electrolyte.

  • infinite dilution, each ion makes a definite contribution to the conductance of an electrolyte whatever be the nature of the other ions of the electrolyte.

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29.

Volume occipied by one molecule of water (density = 1 g cm-3) is

  • 9.0 x 10-23

  • 6.023 x 10-23 cm3

  • 3.0 x 10-23 cm3

  • 3.0 x 10-23 cm3

332 Views

30.

Which of the following complexes exhibits the highest paramagnetic behaviour?

Where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities

(At. no. ; Ti = 22, V = 23, Fe =26, Co = 27)

  • [V(gly)2 (OH)2 (NH3)2]+

  • [Fe(en)(bpy)(NH3)2]+

  • [CO(OX)2(OH)2]-

  • [CO(OX)2(OH)2]-

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