Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

The function of anhydrous AlCl3 in the Friedel-Craft's reaction is to :

  • absorb water

  • absorb HCl

  • to produce electrophile

  • to produce nucleophile


C.

to produce electrophile

The function of anhydrous AlCl3 in the Friedel-Craft's reaction is to produce electrophile , eg , in case of Friedel Craft's alkylation reaction ,it produces electrophile as :

CH3-Cl + AlCl3  


12.

The linear molecule is :

  • CH3

  • C2H2

  • NH3

  • H2O


B.

C2H2

Molecule Hybridisation Geometry
CH4       sp3 Tetrahedral
C2H2       sp Linear
NH3       sp3 Pyramidal (due to 1 Ip)
H2O       sp3 V-shaped (due to 2 lp)

13.

When two double bonds are present on adjacent carbon atoms , the diene is called as :

  • conjugated diene

  • cumulative diene

  • isolated diene

  • None of these


B.

cumulative diene

When two double bonds are present on adjacent carbon atoms , the diene is called cumulative diene .Allene (C3H4) is the simplest example of cumulative diene .

H2C=C=CH2 (allene)


14.

Lindlar's catalyst/H2RCCR Na/NH3 A ,

A and B are geometrical isomers (RCH=CHR)

  • A is cis , B is trans

  • A is trans , B is cis

  • A and B both are cis

  • A and B both are trans


B.

A is trans , B is cis


15.

An element with atomic number 84 and mass number 218 loses one a-particle and two β-particles in three successive stages .The resulting element will have :

  • at. no. 84 and mass no. 214

  • at no. 82 and mass no. 214

  • at. no. 84 and mass no. 218

  • at. no. 82 and mass no. 218


A.

at. no. 84 and mass no. 214

Let element is 'A'

84A218 -α particles 82B214 -β 83C214 -β 84D214

Hence , the resulting element (D) will have at. no. 84 and mass no. 214 .


16.

The homologue of ethyne is :

  • C2H4

  • C3H6

  • C3H3

  • C3H4


D.

C3H4

The successive members of a homologous series differ by a-CH2 group or by 12 + 2 x 1 = 14 mass unit .

Hence , the homologue of  HCCH (ethyne , C2H2) is CH3-CCH (propyne , C3H4) .


17.

Calcium burns in nitrogen to produce a white powder which dissolves in sufficient water to produce a gas A and an alkaline solution .The solution on exposure to air produces a thin solid layer of B on the surface .The compounds A and B will be :

  • Ca3N2 , NH3

  • NH3 , CO2

  • Ca(OH)2 , CaCO3

  • NH3 , CaCO3


D.

NH3 , CaCO3

A = NH3 and B = CaCO3

The reactions are as follows

3CaN2 + N2  Ca3N2calcium nitride

Ca3N2 + 6H23Ca(OH)2 + 2NH3 (A)

Ca(OH)2CO2from air  CaCO3 (B) + H2O(Solid layer is due to CaCO3)


18.

Consider the reaction ,

Fe2+  Fe3+ + e-

  • the reaction towards the left is a reduction

  • the reduction towards the right is a reduction

  • the reaction towards the right is an oxidation

  • the reaction towards the right is an oxidation and the reaction towards the left is an reduction


D.

the reaction towards the right is an oxidation and the reaction towards the left is an reduction

Fe2+  Fe3+ + e-

The reaction towards the right is an oxidation reaction because Fe2+ ion loose one electron and changes into Fe3+ ion .The reaction towards the left is an reduction reaction because Fe3+ ion gain one electron and changes into Fe2+ ion .


19.

Structure of (SiO4)4- ion is :

  • tetrahedral

  • square planar

  • octahedral

  • planar triangular


A.

tetrahedral

(SiO4)4- ions are the basic structural units of silicates and arranged tetrahedrally .

discrete SiO44- tetrahedron


20.

An organic substance containing carbon , hydrogen and oxygen gave the following percentage composition .

C = 40.687 % , H = 5.085% and O = 54.228 % 

What is the empirical formula of the compound ?

  • CH3O

  • C2H2O

  • CH4O

  • C2H3O2


D.

C2H3O2

Symbol Percentage Relative no. of moles

Simplest molar ratio

Simplest whole no. molar ratio
C 40.687 40.68712 = 3.390 3.3903.389 = 1       2
H 5.085 5.0851 = 5.085 5.0853.389 = 1.5       3
O 54.228 54.22816 = 3.389 3.3893.389 = 1        2