Which of the following complex compounds will exhibit highest paramagnetic behaviour ?
At. no. : Ti = 22, Cr = 24, Co = 27, Zn = 30
[Ti(NH3)6]3+
[Cr(NH3)6]3+
[Co(NH3)6]3+
[Co(NH3)6]3+
Which of the following is not a fat soluble vitamin?
Vitamin- B - complex
Vitamin -D
Vitamin -E
Vitamin -E
Which of the statement about 'Denaturation' given below are correct?
Statements,
A) Denaturation of proteins causes loss of secondary and tertiary structures of the protein.
B) Denaturation leads to the conversion of double strand of DNA into single strand.
C) Denaturation affects primary structure which gets distroyed.
(B) and (C)
(A) and (C)
(A) and (B)
(A) and (B)
Which of the following compounds undergoes nucleophilic substitution reaction most easily?
The order of reactivity of phenyl magnesium bromide (phMgBr) with the following compounds.
III > II> I
II > I > III
I > III > II
I > III > II
D.
I > III > II
Since alkyl group has +I -effect and aryl group has +R - effect, thus, greater the number of alkyl and aryl groups attached to the carbonyl group, its reactivity towards nucleophilic addition reaction. Secondly, as the steric crowding on carbonyl group increases, the reactivity decreases accordingly.
therefore, correct reactivity order for reaction with PhMgBr is
The IUPAC name of the following compound
trans - 2- chloro - 3 - iodo - 2 - pentene
cis - 3- iodo - 4- chloro - 3- pentene
trans - 3- iodo - 4- chloro - 3- pentene
trans - 3- iodo - 4- chloro - 3- pentene
Match the compounds given in the list I with List II and select the suitable option using the code given below.
|
List I |
|
List II |
A. |
Benzaldehyde |
1. |
Phenolphtalein |
B. |
Phthalic anhydride |
2. |
Benzoin Condensation |
C. |
Phenyl benzoate |
3. |
Oil of wintergreen |
D. |
Methyl salicylate |
4. |
Fries rearrangement |
A
|
B
|
C
|
D
|
4
|
1
|
3
|
2
|
A
|
B | C | D |
4 | 2 | 3 | 1 |
A
|
B | C | D |
2 | 3 | 4 | 1 |
A
|
B | C | D |
2 | 3 | 4 | 1 |
Consider the reactions
The mechanisms of reactions (i) and (ii) are respectively
SN1 and SN2
SN1 and SN1
SN2 and SN2
SN2 and SN2
A organic compound 'A' on treatment with NH3 gives 'B' which on heating gives 'C', 'C" when treated with Br2 in the presence of KOH produces ethylamine. Compound ' A' is
CH3COOH
CH3CH2CH2COOH
CH3(CH3)CHCOOH
CH3(CH3)CHCOOH