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NEET Chemistry Solved Question Paper 2011

Long Answer Type

41.

In 'x' mL 0.3 N HCl, the addition of 200 mL distilled water or addition of 100 mL 0.1 N NaOH, gives the same final acid strength. Determine 'x'.

42.
Compound A treated with NaNH₂ followed by CH₃CH₂Br gave compound B. Partial hydrogenation of compound B produced compound C, which on ozonolysis gave a carbonyl compound D, (C₂H₅O). Compound D did not respond to the iodoform test with I₂/KI and NaOH. Find out the structures of A, B, C and D.

$\underset{(A)}{{CH}_{3} {CH}_{2} C \equiv CH}$ $\to_{- {NH}_{3}}^{{NaNH}_{2}}$ CH₃CH₂C $\equiv \bar{C} \overset{+}{Na}$ $\to \underset{(B)}{{CH}_{3} {CH}_{2} C \equiv {CCH}_{2} {CH}_{3}}$ $\to_{hydrogenation}^{partial}$ $\underset{(C)}{{CH}_{3} {CH}_{2} CH \equiv {CHCH}_{2} {CH}_{3}}$ $\to_{(ii) Zn + H_{2} O}^{(i) O_{3}}$ $\underset{(D)}{2 {CH}_{3} {CH}_{2} CHO}$

As compound (D) does not have CH₃-C=O group, it does not give iodoform reaction.

43.

The bacterial growth follows the rate law, dN/dt = kN where k is a constant and 'N' is the number of bacteria cell at any time. If the population of bacteria (number of cell) is doubled in 5 min find the time in which the population will be eight times of the initial one?

44.

An organic compound with molecular formula C₉H₁₀O forms 2, 4-DNP derivative, reduces Tollen's reagent and undergoes Cannizaro reaction. On vigorous oxidation, it gives a dicarboxylic acid which is used in the preparation of terylene. Identify the organic compound.

45.

Deep blue CuSO₄^.5H₂O is converted to a bluish-white salt at 100^oC. At 250^oC and 750^oC it is then transformed to white powder and black material respectively. Identify the salts.