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NEET Chemistry Solved Question Paper 2011

Long Answer Type

41.

In 'x' mL 0.3 N HCl, the addition of 200 mL distilled water or addition of 100 mL 0.1 N NaOH, gives the same final acid strength. Determine 'x'.

42.

Compound A treated with NaNH₂ followed by CH₃CH₂Br gave compound B. Partial hydrogenation of compound B produced compound C, which on ozonolysis gave a carbonyl compound D, (C₂H₅O). Compound D did not respond to the iodoform test with I₂/KI and NaOH. Find out the structures of A, B, C and D.

43.
The bacterial growth follows the rate law, dN/dt = kN where k is a constant and 'N' is the number of bacteria cell at any time. If the population of bacteria (number of cell) is doubled in 5 min find the time in which the population will be eight times of the initial one?

As dN/dt = kN (It is a Ist order reaction)

Integrated rate equation for Ist order reaction

k = 2.303/t log N/N_o

$∵$ when t = 5 min, N = 2N_o

$∴$ k = 2.303/5 log 2N_o/N_o

or k = 2.303/5 log 2

for N = 8N_o , t = ?

$∴$ t = 2.303/k log 8N_o/N_o

By putting the value of k

t = $(\frac{2.303}{\frac{2.303}{5} \log 2})$ log 8N_o/N

or t = $\frac{5 \times 3 \log 2}{\log 2}$ = 15 min

44.

An organic compound with molecular formula C₉H₁₀O forms 2, 4-DNP derivative, reduces Tollen's reagent and undergoes Cannizaro reaction. On vigorous oxidation, it gives a dicarboxylic acid which is used in the preparation of terylene. Identify the organic compound.

45.

Deep blue CuSO₄^.5H₂O is converted to a bluish-white salt at 100^oC. At 250^oC and 750^oC it is then transformed to white powder and black material respectively. Identify the salts.