There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there?

• 20

• 60

• 50

• 50

B.

60

Let the number of deer and peacock be x and y.
So, as per question
                   x + y = 80                            ...(i)
                  4x + 2y = 200
or                  2x + y = 100                      ...(ii)
Solving the Eq.(i) and Eq. (ii), we get, x  = 20, y = 60
Hence, the number of peacock  = 60