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The age of the father 4 years ago was 8 times the age of his son. At present, the
father's age is 4 times that of his son. Find the present age of the son.

  • 9 years

  • 7 years

  • 14 years

  • 18 years


B.

7 years

Let the present age of son = x years
Therefore,
the present age of father = 4x years
According to the question,
4 years ago
8(x-4) = 4x-4
8x-32 = 4x-4
8x-4x = 32-4
4x = 28
x = 28/4 = 7 years

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