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    Units and Measurement
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    Fill in the blanks by suitable conversion of units 
    (a) 1 kg m2s–2= ....g cm2s–2

    107

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    1 space kg space equals space 10 cubed space straight g space 1 space straight m squared space equals space 10 to the power of 4 space end exponent cm squared space 1 space kg space straight m squared space straight s to the power of negative 2 end exponent space equals space 1 space kg cross times space 1 space straight m squared space cross times 1 space straight s to the power of negative 2 end exponent space space space space space space space space space space space space space space space space space space space space space space space equals space space space space 10 cubed space straight g space cross times space 10 to the power of 4 space cm squared space cross times space 1 space straight s to the power of negative 2 end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 10 to the power of 7 space end exponent gcm squared straight s to the power of negative 2 end exponent
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    Fill in the blanks : 
    c) A vehicle moving with a speed of 18 km h–1covers....m in 1 s

    5 

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    1 space km divided by hr space equals space fraction numerator 1 cross times 1000 over denominator 3600 end fraction space equals space 5 over 18 space straight m divided by straight s space straight i. straight e. comma space 18 space km divided by hr space equals space 18 cross times 5 over 18 equals space 5 space straight m divided by straight s space Now comma space Distance space equals space speed space cross times space time space space space space space space space space space space space space space space space space space space equals space 5 cross times 1 space equals space 5 space straight m
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    Fill in the blanks: 
    d) The relative density of lead is 11.3. Its density is ....g cm–3or ....kg m–3.

    11.3

    , 11.3 x 103

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    Relative space density space equals space fraction numerator Density space of space straight a space substance space over denominator Density space of space water end fraction Density space of space water space equals space 1 space gm divided by cm cubed space Density space of space lead space equals space Relative space density space of space lead space cross times space density space of space water space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 11.3 cross times 1 space equals space 11.3 space straight g divided by cm cubed space 1 space straight g space equals space 1 over 1000 space kg 1 space cm cubed space equals space 10 to the power of negative 6 end exponent space straight m cubed space 1 space straight g divided by cm cubed space equals space 10 to the power of negative 3 end exponent over 10 to the power of negative 6 end exponent space kg divided by straight m cubed space equals space 10 cubed space kg divided by straight m cubed space therefore space 11.3 space straight g divided by cm cubed space equals space 11.3 space cross times space 10 cubed space kg divided by straight m cubed
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    The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to
    ...(mm)2

    1.5 x 104 mm2

    The total surface area of a cylinder of radius r and height h is

    S = 2πr (r + h).

    Given space that comma space straight r space equals space 2 space cm space equals space 2 cross times 10 space mm space equals space 20 space mm space straight h space equals space 10 space cm space equals 10 space cross times 10 space mm space equals space 100 space mm space So comma space Surface space area comma space straight S space equals space 2 cross times 3.14 cross times 20 cross times left parenthesis 20 plus 100 right parenthesis space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 15072 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1.5 space cross times 10 to the power of 4 space mm squared

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    Fill in the blanks: 
    a) The volume of a cube of side 1 cm is equal to .....m3

    10-6 

    1 cm = 1 space cm space equals space 1 over 100 space straight m So comma space volume space of space the space cube space equals space 1 space cm cubed space straight i. straight e. comma space 1 space cm cubed space equals space open parentheses 1 over 100 close parentheses cross times space open parentheses 1 over 100 close parentheses cross times space open parentheses 1 over 100 close parentheses space straight m space therefore space 1 space cm cubed space equals space 10 to the power of negative 6 end exponent space straight m cubed So space volume space of space straight a space cube space of space side space 1 space cm is space equal space to space 10 to the power of negative 6 end exponent space cm cubed.

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