﻿ From the tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle to hit the ground is n times that taken by it to reach the highest point of its path. The relation between H,u and n is from Physics Gravitation Class 11 Manipur Board

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From the tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle to hit the ground is n times that taken by it to reach the highest point of its path. The relation between H,u and n is

• 2gH = n2u2

• gH = (n-2)2u2

• 2gH = nu2(n-2)2u2

• gH = (n-2)2u2

C.

2gH = nu2(n-2)2u2

Time is taken to reach the maximum height t1 = u/g

If t2 is the time taken to hit the ground,
i.e,

Time is taken to reach the maximum height t1 = u/g

If t2 is the time taken to hit the ground,
i.e,

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The position co-ordinates of two particles of masses m1 and m2are (x1, y1, z1) and (x2, y2, z2) respectively. Find the coordinates of the centre of mass.

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Let the position coordinates of the centre of mass be (X, Y, Z).

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Since,

Comparing the coefficients of  , we get

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