ï»¿ From the tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle to hit the ground is n times that taken by it to reach the highest point of its path. The relation between H,u and n is from Physics Gravitation Class 11 Manipur Board

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From the tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle to hit the ground is n times that taken by it to reach the highest point of its path. The relation between H,u and n is

• 2gH = n2u2

• gH = (n-2)2u2

• 2gH = nu2(n-2)2u2

• gH = (n-2)2u2

C.

2gH = nu2(n-2)2u2

Time is taken to reach the maximum height t1 = u/g

If t2 is the time taken to hit the ground,
i.e,Â

Time is taken to reach the maximum height t1 = u/g

If t2 is the time taken to hit the ground,
i.e,Â

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The position co-ordinates of two particles of masses m1Â and m2are (x1, y1, z1) and (x2, y2, z2) respectively. Find the coordinates of the centre of mass.

The position vectors of masses m1Â and m2Â are respectively,

Let the position coordinates of the centre of mass be (X, Y, Z).

Therefore the position vector of centre of mass is,

Since, Â  Â

Â

Comparing the coefficients of Â , we get

Â

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