﻿ A stream of water flowing horizontally with a speed of 15 m s–1 gushes out of a tube of cross-sectional area 10–2m2, and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound? from Physics Laws of Motion Class 11 Manipur Board

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A stream of water flowing horizontally with a speed of 15 m s–1 gushes out of a tube of cross-sectional area 10–2m2, and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound?

Given,

Speed of the water stream, v = 15 m/s

Cross-sectional area of the tube, A = 10–2 m2

Volume of water coming out from the pipe per second,

VAv

= 15 × 10–2 m3/s

Density of water, ρ = 103 kg/m

Mass of water flowing out through the pipe per second = ρ ×V

= 150 kg/s

The water strikes the wall and does not rebound.

Therefore, according to Newton's second law of motion,

Force exerted by the water on the wall,

F = Rate of change of momentum =

=

= 150 × 15

= 2250 N
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