﻿ A ball is released from the top of a tower of height h metres. It takes T seconds to reach the ground. What is the position of the ball in T/3 seconds? from Physics Laws of Motion Class 11 Manipur Board

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A ball is released from the top of a tower of height h metres. It takes T seconds to reach the ground. What is the position of the ball in T/3 seconds?

• h/9 metres from the ground

• 7h/9 metres from the ground

• 8h/9 metres from the ground

• 17h/18 metres from the ground.

C.

8h/9 metres from the ground

second law of motion
therefore s = h/9 m
Hence, the position of ball from the ground= h- h/9 = 8h/9 m

second law of motion
therefore s = h/9 m
Hence, the position of ball from the ground= h- h/9 = 8h/9 m

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