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Motion in A Plane

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Physics Part I

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Physics

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Class 10 Class 12
A force inclined at angle 37° with the horizontal has vertical component 42N. Find the magnitude of force and magnitude of its horizontal component. (Take sin 37° = 0·6 and cos 37° = 0·8)

Let F be the magnitude of force.

If force vector subtends an angle θ with the horizontal, then horizontal and vertical components of force respectively, 

              space space space straight F subscript straight x equals space Fcosθ     and     straight F subscript straight y space equals space Fsinθ

Here,

Angle with which the force is inclined to the horizontal, straight theta equals 37 degree

Vertical component of the force, straight F subscript straight y equals 42 space straight N 

So, magnitude of force is found using, 

∴               42 space equals space straight F space sin 37 degree space equals space straight F space cross times space 0.6

Force, straight F space equals space 70 straight N

Horizontal component, straight F subscript straight x equals Fcosθ space equals space 70 cross times 0.8 space equals space 56 straight N            
       
144 Views

Give three examples of scalar quantities.

Mass, temperature and energy
769 Views

What is a scalar quantity?

A physical quantity that requires only magnitude for its complete specification is called a scalar quantity.
1212 Views

What are the basic characteristics that a quantity must possess so that it may be a vector quantity?

A quantity must possess the direction and must follow the vector axioms. Any quantity that follows the vector axioms are classified as vectors. 


814 Views

What is a vector quantity?

A physical quantity that requires direction along with magnitude, for its complete specification is called a vector quantity.
835 Views

Give three examples of vector quantities.

Force, impulse and momentum.
865 Views