﻿ A force inclined at angle 37° with the horizontal has vertical component 42N. Find the magnitude of force and magnitude of its horizontal component. (Take sin 37° = 0·6 and cos 37° = 0·8) from Physics Motion in A Plane Class 11 Manipur Board

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A force inclined at angle 37° with the horizontal has vertical component 42N. Find the magnitude of force and magnitude of its horizontal component. (Take sin 37° = 0·6 and cos 37° = 0·8)

Let F be the magnitude of force.

If force vector subtends an angle θ with the horizontal, then horizontal and vertical components of force respectively,

and

Here,

Angle with which the force is inclined to the horizontal,

Vertical component of the force,

So, magnitude of force is found using,

∴

Force,

Horizontal component,

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A quantity must possess the direction and must follow the vector axioms. Any quantity that follows the vector axioms are classified as vectors.

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