A particle moves from point (2, 3, 5) to (8, -4, 2) when a force
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A particle moves from point (2, 3, 5) to (8, -4, 2) when a force of 3 straight i with hat on top minus 7 straight j with hat on top minus straight k with hat on top unit is applied on it. Find the work done by the force.


Given, a particle moves from point P(2,3,5) to Q(8,-4,2). 

Force applied on th particle, F =  

Therefore, the displacement undergone by the particle is, 
              

                 

Therefore work done by force is, 

  

               J

 

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For what value of c the vector 2 straight i with hat on top plus straight c straight j with hat on top will be perpendicular to:
(i) Z-axis      (ii) Y-axis?


(i) Vector  is zero.

i.e.                       

                  

                     

The equation is satisfied for all values of c.

Therefore  is always perpendicular to Z-axis whatever the value of c.

(ii) Similarly        

                    

                            

                                    

∴   is perpendicular to Y-axis if c = 0.

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#6 {main}</pre> and straight B with rightwards arrow on top space equals space minus 4 straight i with hat on top plus 2 straight j with hat on top are perpendicular to each other.


Given,       

and            

  have to be perpendicular to each other.

To prove that we will find the dot product.

  

         

Hence     . 

Since, the dot product is zero the two vectors are perpendicular to each other. 

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#6 {main}</pre>


Here,    

Therefore the magnitude of vector 

 

      

Now the unit vector in direction of  is, 

     

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#6 {main}</pre> and straight B with rightwards arrow on top space equals space 2 straight i with hat on top plus straight j with hat on top minus 4 straight k with hat on top?


Given that,

           

and      

Let straight theta be the angle between the given two vectors.

We know,  

∴               

Now           

                         

Magnitude is given by,

 



 Thus, angle between the vectors,

 

                   

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