﻿ A particle starts with a velocity of 200 cm/s and moves in a straight line with a retardation of 10 cm/s2. Find the time it takes to describe 1500 cm and explain the double answers.  from Physics Motion in A Plane Class 11 Manipur Board

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A particle starts with a velocity of 200 cm/s and moves in a straight line with a retardation of 10 cm/s2. Find the time it takes to describe 1500 cm and explain the double answers.

Here, we have

Initial velocity, u = 200 cm/s

Acceleration, a = -10 cm/s2

Distance travelled, s = 1500 cm

Time taken, t = ?

Using the relation,

s = ut + 1/2 at2

1500 = 200 t + 1/2(-10)t2

On solving the equation,we get

t = 10 s or t = 30 s

Here, the value of 10 s corresponds to the time when the particle first arrives at the given location. It then crosses this point and at the end of 20 s, its velocity is just 0.

The particle then returns and at the end of 10 s more, is again at the given location from the starting point.

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