A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flights in the two cases, then the product of the two time of flights is proportional to

  • R2

  • 1/R2

  • 1/R

  • 1/R


D.

1/R

straight t subscript 1 straight t subscript 2 space equals space fraction numerator 2 straight u squared sin space 2 straight theta over denominator straight g squared end fraction space equals space fraction numerator 2 straight R over denominator straight g end fraction
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A particle is moving eastwards with a velocity of 5 m/s in 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is

  • fraction numerator 1 over denominator square root of 2 end fraction straight m divided by straight s squared spacetowards north-east
  • 1 half straight m divided by straight s squared spacetowards north.
  • zero

  • zero


D.

zero



straight a with rightwards arrow on top space equals space fraction numerator stack straight V subscript straight f with rightwards arrow on top minus stack straight V subscript straight i with rightwards arrow on top over denominator straight t end fraction space
space equals space fraction numerator 5 straight j with hat on top minus 5 straight i with hat on top over denominator 10 end fraction space equals 1 half space left parenthesis straight j with hat on top minus straight i with hat on top right parenthesis
therefore straight a space equals space fraction numerator 1 over denominator square root of 2 end fraction ms to the power of negative 2 end exponent space towards space north space west
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A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity ‘v’ that varies as v= α√x . The displacement of the particle varies with time as

  • t3

  • t2

  • t

  • t


B.

t2

straight v equals space straight alpha square root of straight x
dx over dt space equals space straight alpha square root of straight x space space space space open parentheses therefore space straight v space equals space dv over dt close parentheses
fraction numerator dx over denominator square root of straight x end fraction space equals space straight alpha space dt
Perform space integration
integral subscript 0 superscript straight x fraction numerator dx over denominator square root of straight x end fraction space equals space integral subscript 0 superscript straight t straight alpha space dt
because space at space straight t space equals space 0 comma space straight x space equals space 0 space and space let space at space any space time space straight t comma space particle space is space at space straight x right square bracket
rightwards double arrow right enclose space fraction numerator straight x to the power of 1 divided by 2 end exponent over denominator 1 divided by 2 end fraction end enclose subscript 0 superscript straight x space equals space αt
rightwards double arrow space straight x to the power of 1 divided by 2 end exponent space equals space straight alpha over 2 straight t
rightwards double arrow space straight x space equals space straight alpha squared over 4 straight x space straight t squared space rightwards double arrow space straight x proportional to space straight t squared
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A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then

  • S=ft

  • S= ft2/72

  • S = 1/2 ft2

  • S = 1/2 ft2


B.

S= ft2/72



straight S space equals space fraction numerator ft subscript 1 superscript 2 over denominator 2 end fraction
straight v subscript straight o space equals square root of 2 Sf end root
During space retardation
straight S subscript 2 space equals space 2 straight S
During space constant space velocity
15 straight S space minus 3 straight S space equals space 12 space straight S space equals straight v subscript straight o straight t
rightwards double arrow space straight S space equals ft squared over 72
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A parachutist after bailing outfalls 50 m without friction. When a parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3 m/s. At what height, did he bail out?

  • 91 m

  • 182 m

  • 293 m

  • 293 m


C.

293 m

straight s equals space 50 space plus open parentheses fraction numerator 3 squared minus left parenthesis 2 straight x 10 straight x 50 right parenthesis over denominator 2 left parenthesis negative 2 right parenthesis end fraction close parentheses
space equals space 293 space straight m
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