A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 s is s1 and that covered in the first 20 s is s2, then
s2 = 2s1
s2 = 3s1
s2 = 4 s1
s2 = 4 s1
C.
s2 = 4 s1
If the particle is moving in a straight line under the action of a constant force then distance covered s = ut + at2 /2
since the body start from rest u = 0
therefore, s = at2/2
Now,
Two bodies of mass 1 kg have position vectors,
respectively.The centre of mass of this system has a position vector
B.
The position vector of centre of mass
Point to know:
The centre of mass changes its position only under the translatory motion. There is no effect of rotatory motion on centre of mass of the body.
The distance travelled by a particle starting from rest and moving with an acceleration 4/3 ms-2 in the third second is
6 m
4 m
10/3
10/3
C.
10/3
Distance travelled by the particle in nth second
Where u is initial speed and a is an acceleration of the particle.
Here, n = 3, u =0, a = 4/3 m/s2
is the force acting on a particle having position vector 
be the the torque of this force about the origin, then
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