﻿ A ball thrown up is caught by the thrower 4 s after start. What is the height to which the ball has risen? from Physics Motion in A Plane Class 11 Manipur Board

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A ball thrown up is caught by the thrower 4 s after start. What is the height to which the ball has risen?

Time of ascent = Time of descent.

Therefore,

t1 + t2 = 4

t2 + t2 = 4

This implies,

t2 = 2 sec

Now, taking vertical downward motion of the ball from the highest point to surface of earth we have,

u = 0, a = 10 m/s, t = 2 s, s = ?

Now, using the formula,

s = ut + 1/2 at2

=
= 20 m

This is the height to which the ball has risen.

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