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Class 10 Class 12

At what angle of projection the horizontal range is four times the maximum height attained by the projectile?

Given, horizontal range is four times the maximum height attained by the projectile.

i.e., R = 4H

We know,

Substituting R = 4H in the above equation,
we get,




i.e.,

167 Views

Show that the ratio of the horizontal range to the maximum height attained by projectile is equal to 4 cot

straight theta

and is independent of speed of projection.

The horizontal range attained by projectile projected with velocity u at angle θ is,

Maximum height attained by projectile projected with velocity u at angle θ is,

The ratio of horizontal range to maximum height is given by,

Hence, the result proved.

118 Views

Two projectiles are projected with same velocity at same angle, one on the earth and second on the moon. If the projectile acquires the maximum height of H on the earth, then what will be the maximum height attained by the projectile on the moon?

Maximum height attained by the projectile on the earth is,

Acceleration due to gravity on the moon is g/6. Therefore maximum height attained by the projectile on the moon is,

Thus maximum height attained on the moon is six times the maximum height attained on the earth.

122 Views

Why the electrons in beam from an electron gun do not fall as much as a water molecule in stream from a hose due to gravity?

Vertical distance by which projectile falls while travelling a given distance in horizontal direction is,

From the above relation,

Velocity of electron from electron gun is greater than the water molecule from hose. Therefore, for a given horizontal displacement x, the vertical distance by which the electron beam falls is less than that for water molecule.

140 Views

A body of mass 2 kg is projected with a velocity 60 m/sec at an angle of 30°. What is the height of the body from ground at t = 2·5s? (Take g = 10 m/s²)

The height of the body from ground at any instant is given by,