A particle starts moving from position of rest under a constant acceleration. If it travels a distance x in t second, what distance will it travel in next t second?
Given,
Initial velocity, u = 0
Distance travelled, s = x
Time taken to travel x distance, t = t sec
Now, using the relation,
we have
x = 0 + 1/2 at2 ... (1)
Let the body travel a distance y in next t seconds.
The total distance travelled in t+t = 2t sec will be (x+y).
Therefore,
(x+y) = 1/2 a (2t)2
= 1/2a x 4t2 ... (2)
Dividing equation (2) by (1), we have
Total distance to be travelled, s = 100 + 1000 = 1100 m
Velocity, v = 60 km/hr = 50/3 m/s
Therefore,
Time taken to cross the bridge, t =
Yes, for example if you are throwing a dart at the board, position the dart a little above the target in order to hit the target. This will enable you to hit the target accurately as the dart will follow a projectile motion.
During the vertical fall of a body, the time taken for the body to fall is given by,
,
which is independent of the mass of the body.
Hence, both the bodies will reach the ground simultaneously.