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#6 {main}</pre>, then what is the relative velocity of B w.r.t.A?


The relative velocity of B w.r.to A is same in magnitude but opposite in direction. 

That is the relative velocity is -straight v with rightwards harpoon with barb upwards on top

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A balloon is ascending at the rate of 20 m/sec. When it is at a height 100 m from ground, a packet is dropped from the balloon.
What will be the velocity of the packet w.r.t. 
(i) ground

(ii) balloon, when it was just dropped?  

Speed at which the balloon is ascending, v = 20 m/s

Height of balloon from the ground = 100 m

With respect to ground, the velocity of the packet will be 20 m/sec upward.

With respect to balloon, its velocity will be zero.

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When the magnitude of relative velocity is equal to the sum of the magnitude of the velocities of two bodies?


When the two bodies are moving in opposite direction along a straight line, then the magnitude of relative velocity is equal to the sum of the magnitude of the velocities of two bodies.
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Two particles A and B are moving with speed u and v in mutually perpendicular directions. What is the magnitude of the relative velocity of B w.r.t. A? 

The magnitude of the relative velocity of B w.r.t A is, 

                     vrsquare root of straight u squared plus straight v squared end root

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A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/hr and second half of distance at speed v. The average speed is 48 km/hr. Find the value of v? 

We have, 

Distance moved, s = 2 km 

Velocity, u1 = 40 km/hr

u2 = v 

Average velocity = fraction numerator 0.2 over denominator 48 end fraction space equals space fraction numerator 0.1 over denominator 40 end fraction space plus space fraction numerator 0.1 over denominator v end fraction

On solving the equation, we get

v = 60 km/hr

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