﻿ A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then from Physics Motion in A Plane Class 11 Manipur Board

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A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then

• S=ft

• S= ft2/72

• S = 1/2 ft2

• S = 1/4 ft2

B.

S= ft2/72

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A physical quantity that requires direction along with magnitude, for its complete specification is called a vector quantity.
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