ï»¿ Two trains A and B of length 400 m each are moving on two parallel tracks with aÂ uniform speed of 72 km hâ€“1 in the same direction, with A ahead of B. The driver ofÂ B decides to overtake A and accelerates by 1 m sâ€“2. If after 50 s, the guard of B justÂ brushes past the driver of A, what was the original distance between them ? from Physics Motion in Straight Line Class 11 Manipur Board

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Motion in Straight Line

Physics Part I

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Two trains A and B of length 400 m each are moving on two parallel tracks with aÂ uniform speed of 72 km hâ€“1 in the same direction, with A ahead of B. The driver ofÂ B decides to overtake A and accelerates by 1 m sâ€“2. If after 50 s, the guard of B justÂ brushes past the driver of A, what was the original distance between them ?

In case of train A:Â

Initial velocity,Â uÂ = 72 km/h = 20 m/s

Time,Â tÂ = 50 s

Since the train is moving with uniform velocity,Â

Acceleration,Â aIÂ = 0

Now, using second equation of motion,Â

Distance covered by train A is given by,Â

Â

For train B,Â

Initial velocity, uB =Â 72 km/h = 20 m/s

Acceleration,Â aÂ = 1 m/s2Â

Time,Â tÂ = 50 s

Now, using second equation of motion,Â

Distance travelled by second train B is,Â

Length of both trains = 2Â
Therefore, the original distance between the driver of train A and the guard of train B = 2250 - 1000 - 800
= 450m.

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