At t= 0.3 sec,
Negative, Negative, Positive.
At t= 1.2 sec,
Positive, Positive, Negative
At t= -1.2 sec
Negative, Positive, Positive
For simple harmonic motion (SHM) of a particle, acceleration (a) is given by,
a = – ω2x ; ω → angular frequency … (i)
t = 0.3 s
In this time interval, x is negative. Thus, the slope of the position-time graph will also be negative. Therefore, both position and velocity are negative.
However, using equation (i), acceleration of the particle will be positive.
t = 1.2 s
In this time interval, x is positive. Thus, the slope of the x-t graph will also be positive. Therefore, both position and velocity are positive.
However, using equation (i), acceleration of the particle comes to be negative.
t = – 1.2 s
In this time interval, x is negative. Thus, the slope of the x-t plot will also be negative. Since both x and t are negative, the velocity comes to be positive.
From equation (i), it can be inferred that the acceleration of the particle will be positive.
n | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
Sn | 0.5 | 1.5 | 2.5 | 3.5 | 4.5 | 5.5 | 6.5 | 7.5 | 8.5 | 9.5 |