The dimensions of left parenthesis straight mu subscript straight o straight epsilon subscript straight o right parenthesis to the power of negative 1 divided by 2 end exponent are

  • [L1/2 T-1/2]

  • [L-1T]

  • [LT-1]

  • [LT-1]


C.

[LT-1]

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The dimensions of left parenthesis straight mu subscript straight o straight epsilon subscript straight o right parenthesis to the power of negative 1 divided by 2 end exponent are

  • [L-1T]

  • [LT-]

  • [L-1/2 T1/2]

  • [L-1/2 T1/2]


B.

[LT-]

This expression for speed of light and the dimensions of speed of light are [LT-1].

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If force (F), velocity (v) and time (T) are taken as fundamental units, then the dimensions of mass are

  • [FvT-1]

  • [FvT-2]

  • [Fv-1T-1]

  • [Fv-1T-1]


D.

[Fv-1T-1]

We know that,

F = ma

That is,

F = mv/t


So, 

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The cylindrical tube of a spray pump has radius R, one end of which has n fine holes, each of radius r. if the speed of the liquid in the tube is v, the speed of the ejection of the liquid through the holes is

  • vR2/n2r2

  • vR2/nr2

  • vR2/n3r2

  • vR2/n3r2


B.

vR2/nr2

During the streamline of viscous and incompressible fluid through a pipe varying cross -section, the product of the area of cross section and normal fluid velocity (Av) remains constant throughout the flow.

Consider a cylindrical tube of a spray pump has radius R, one end having n fine holes, each of radius r and speed of liquid in the tube is v as shown in the figure.

According to equation of continuity

Av = constant

where A is a cylindrical tube and v is the velocity of the liquid in a tube. 

Volume in flow rate = volume an outflow rate

πR2v = nπr2v'

v' = R2v/nr2

Thus, speed of the ejection of the liquid through the holes is R2v/nr2



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In an experiment, four quantities a,b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows:
P = fraction numerator straight a cubed straight b squared over denominator cd end fraction space percent sign, error in P is

  • 14 %

  • 10 %

  • 7 %

  • 7 %


A.

14 %

Here, P = 
Therefore,




= 3 x1 + 2 x 2 + 3 +4 

= 3 + 4 + 3 + 4

= 14 %

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