The velocity v of a particle at time t is given by  where a, b

The length, breadth and thickness of a block are given by l = 12 cm, b = 6 cm and t = 2.45 cm. The volume of the block according to the idea of significant figures should be

  • 1 × 102 cm3

  • 2 × 102 cm3

  • 1.76 × 102 cm3

  • None of these


B.

2 × 102 cm3

Using relation for volume

Given:- length of a block  =  12 cm

          breadth of a block  =  6 cm

        thickness of a block  =  2.45cm

V =length  × breadth  × thickness

  =12  × 6  × 2.45  = 176.4

 =1.764 ×102 cm3

The minimum number of significant figures is in thickness, hence the volume will contain only one significant figure.

Therefore V= 2 ×102 cm3 


The physical quantity of the dimensions of length that can be formed out of c, G and e/4πε0 is [c is the velocity of light, G is the universal constant of gravitation and e is charge]

  • 1 over straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets fraction numerator straight e squared over denominator straight G 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets fraction numerator straight e squared over denominator straight G 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent

A.

1 over straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
1964 Views

Advertisement

The velocity v of a particle at time t is given by straight v equals at plus fraction numerator straight b over denominator straight t plus straight c end fraction comma where a, b and c are constants, The dimensions of a, b and c are respectively:

  • open square brackets LT to the power of negative 2 end exponent close square brackets comma space open square brackets straight L close square brackets space and space open square brackets straight T close square brackets
  • open square brackets straight L squared close square brackets space open square brackets straight T close square brackets space and space open square brackets LT squared close square brackets
  • open square brackets LT squared close square brackets comma space open square brackets LT close square brackets space and space open square brackets straight L close square brackets
  • open square brackets LT squared close square brackets comma space open square brackets LT close square brackets space and space open square brackets straight L close square brackets


A.

open square brackets LT to the power of negative 2 end exponent close square brackets comma space open square brackets straight L close square brackets space and space open square brackets straight T close square brackets

According to principle of homogeneity of dimensions, the dimensions of all the terms in a physical expression should be same.
   The given expression is 
                      
From principle of homogeneity
     

502 Views

Advertisement

Dimensions of resistance in an electrical circuit, in terms of the dimension of mass M, of length L, of time T and of current I, would be:

  • [ML2T-3I-1]

  • [ML2T-2]

  • [ML2T-1I-1]

  • [ML2T-1I-1]


D.

[ML2T-1I-1]

Resistance 

484 Views

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of –0.004 cm, the correct diameter of the ball is

  • 0.521 cm

  • 0.525 cm

  • 0.529 cm

  • 0.053


C.

0.529 cm

Diameter of the ball

= MSR + CSR x (least count) - zero error

 = 0.5 cm + 25 x 0.001 - (-0.004)

= 0.5 + 0.025 + 0.004

= 0.529 cm


Advertisement