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The physical quantity of the dimensions of length that can be formed out of c, G and e/4πε0 is [c is the velocity of light, G is the universal constant of gravitation and e is charge]

  • 1 over straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets fraction numerator straight e squared over denominator straight G 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets fraction numerator straight e squared over denominator straight G 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent


A.

1 over straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
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The velocity v of a particle at time t is given by straight v equals at plus fraction numerator straight b over denominator straight t plus straight c end fraction comma where a, b and c are constants, The dimensions of a, b and c are respectively:

  • open square brackets LT to the power of negative 2 end exponent close square brackets comma space open square brackets straight L close square brackets space and space open square brackets straight T close square brackets
  • open square brackets straight L squared close square brackets space open square brackets straight T close square brackets space and space open square brackets LT squared close square brackets
  • open square brackets LT squared close square brackets comma space open square brackets LT close square brackets space and space open square brackets straight L close square brackets
  • open square brackets LT squared close square brackets comma space open square brackets LT close square brackets space and space open square brackets straight L close square brackets

A.

open square brackets LT to the power of negative 2 end exponent close square brackets comma space open square brackets straight L close square brackets space and space open square brackets straight T close square brackets

According to principle of homogeneity of dimensions, the dimensions of all the terms in a physical expression should be same.
   The given expression is 
                      
From principle of homogeneity
     

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The length, breadth and thickness of a block are given by l = 12 cm, b = 6 cm and t = 2.45 cm. The volume of the block according to the idea of significant figures should be

  • 1 × 102 cm3

  • 2 × 102 cm3

  • 1.76 × 102 cm3

  • None of these


B.

2 × 102 cm3

Using relation for volume

Given:- length of a block  =  12 cm

          breadth of a block  =  6 cm

        thickness of a block  =  2.45cm

V =length  × breadth  × thickness

  =12  × 6  × 2.45  = 176.4

 =1.764 ×102 cm3

The minimum number of significant figures is in thickness, hence the volume will contain only one significant figure.

Therefore V= 2 ×102 cm3 


Dimensions of resistance in an electrical circuit, in terms of the dimension of mass M, of length L, of time T and of current I, would be:

  • [ML2T-3I-1]

  • [ML2T-2]

  • [ML2T-1I-1]

  • [ML2T-1I-1]


D.

[ML2T-1I-1]

Resistance 

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A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of –0.004 cm, the correct diameter of the ball is

  • 0.521 cm

  • 0.525 cm

  • 0.529 cm

  • 0.053


C.

0.529 cm

Diameter of the ball

= MSR + CSR x (least count) - zero error

 = 0.5 cm + 25 x 0.001 - (-0.004)

= 0.5 + 0.025 + 0.004

= 0.529 cm


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