Radius of hydrogen atom, r = 0.5 = 0.5 × 10–10 m
Given the relation,Â
Â
Dimension of m = M1 L0 T0
Dimension of mo = M1 L0 T0Â
Dimension of v = M0 L1 T–1
Dimension of v2 = M0 L2 T–2
Dimension of c = M0 L1 T–1
The given formula will be dimensionally correct only when the dimension of L.H.S is the same as that of R.H.S.
This is possible when the factor in the denominator is dimensionless. This is only possible if Â
Hence the correct relation isÂ