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Comets move around the sun in highly elliptical orbits. The gravitational force on the comet due to the sun is not normal to the comet's velocity in general. Yet the work done by the gravitational force over every complete orbit of the comet is zero. Why?

The gravitational force of the Sun does positive work when the comet moves from apogee to perigee and the gravitational force of the Sun does same amount of negative work when it goes from perigee to apogee.

Hence net work done by the gravitational force of the Sun on the comet in one complete cycle is zero.
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Comets move around the sun in highly elliptical orbits. The gravitational force on the comet due to the sun is not normal to the comet's velocity in general. Yet the work done by the gravitational force over every complete orbit of the comet is zero. Why?

The gravitational force is conservative force.

We know that, work done by conservative force is independent of path followed, but depends upon initial and final position. Therefore, over the closed path, the work done by conservative force is zero. 
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Given in Fig. 6.11 are examples of some potential energy functions in one dimension. The total energy of the particle is indicated by a cross on the ordinate axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant.

Total energy of a system is, 

                       Energy = P.E. + K. E. 

∴                          K.E. = E – P.E

The Kinetic energy of a body is a positive quantity.

It cannot be negative.

Therefore, the particle will not exist in a region where K.E. becomes negative.
 
(i) For x > a, P.E. (V0) > E

Therefore, 

K.E. becomes negative.

Hence, the object cannot exist in the region x > a.
 
(ii) For x < a and b, P.E. (V0) > E.

Therefore,

Kinetic Energy becomes negative.

Hence the object cannot be present in the region x < a and x > b.
 
iii) x > a and x < b < –V1

In the given case, the condition regarding the positivity of K.E. is satisfied only in the region between > a and x < b.

The minimum P.E in this case is –V1.

Therfore, K.E. = E – (–V1) = E + V1.

Therefore, for the positivity of the kinetic energy, the total energy of the particle must be greater than –V1.

So, the minimum total energy the particle must have is –V1.

iv)  -b/2 <  x <  a/2 ; a/2 < x < b/2 ; -V1

In the given case, the potential energy (V0) of the particle becomes greater than the total energy (E) for -b/2 < x < b/2 and -a/2 <  x < a/2.

Therefore, the particle will not exist in these regions. 

The minimum potential energy in this case is –V1.

Therefore, K.E.  = E – (–V1) = E + V1.

Therefore, for the positivity of the kinetic energy, the total energy of the particle must be greater than –V1.

So, the minimum total energy the particle must have is –V1.
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The sign of work done by a force on a body is important to understand. State carefully if the following quantities are positive or negative,

(e) Work done by the resistive force of air on a vibrating pendulum in bringing it to rest.


Negative Quantity.

The resistive force of air acts in the direction opposite to the direction of motion of the pendulum. Hence, negative work is done in this case.
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The casing of a rocket in flight burns up due to friction. At whose expense is the heat energy required for burning obtained– the rocket or the atmosphere?

The heat energy required to burn the casing of rocket is at the cost of kinetic energy of the rocket. 
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