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Consider a drop of rain water having mass 1 g falling from a height of 1 km. It hits the ground with a speed of 50 m/s. Take g constant with a value 10 m/s2. The work done by the (i) gravitational force and the (ii) resistive force of air is

  • (i) – 10 J (ii) –8.25 J

  • (i) 1.25 J (ii) –8.25 J

  • (i) 100 J (ii) 8.75 J

  • (i) 100 J (ii) 8.75 J


D.

(i) 100 J (ii) 8.75 J

wg+ wa= Kf– Ki


wa= –8.75 J i.e. work done due to air resistance and work done due to gravity = 10 J

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The diagrams below show regions of equipotentials

A positive charge is moved from A to B in each diagram.

  • Maximum work is required to move q in figure (c).

  • In all the four cases the work done is the same.

  • Minimum work is required to move q in figure (a).

  • Minimum work is required to move q in figure (a).


B.

In all the four cases the work done is the same.

Work was done w = qΔV
ΔV is same in all the cases so work is done will be same in all the cases.

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If force F=5i^+3j^+4k^ makes a displacement of s=6i^-5k^work done by the force is

  • 10units

  • 1225units

  • 5122units

  • 20units


A.

10units

Work done=Force×displacement                    =F.s                   =5i^+3j^+4k^.6i^-5k^                   =5i^+3j^+4k^.6i^+0j^-5k^                   =30+0-20=10 units


The work done in pulling up a block of wood weighing 2 kN for a length of 10 m on a smooth plane inclined at an angle of 15° with the horizontal is

  • 9.82 kJ

  • 89 kJ

  • 4.35 kJ

  • 5.17 kJ


D.

5.17 kJ

Here :- Weight of block;ω = 2kN; Distance d =10m

Angle of inclination on the plane α =150

The block will be pulled up on a smooth plane

Hence,force of resistance due to the inclination 

F =ωsinα = 2×103×Sin 150

=2×103×0.2588

=0.5176 kN

Now work done W = force×displacement =0.1576×103×10=5.17kJ


A particle moves from postionr1=3i^+2j^-6k^  to position  r2=14i^+13j^+9k^  under action of force F=4i^+j^+3k^ N.  The work done will be

 

  • 100J

  • 50J

  • 200J

  • 75J


A.

100J

Using the formula for work doneW=F.r    =F.r2-r1=4i^+j^+3k^ . 14i^+13j^+9k^-3i^+2j^-6k^          =4i^+j^+3k^. 14i^+13j^+9k^-3i^-2j^+6k^     =4i^+j^+3k^. 11i^+11j^+15k^W  =44+11+45                      We know that i.i=j.j=k.k=1   W=100J


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