A liquid exerts a buoyant force of 2.4 kg on a body of mass 6.4 kg when it is immersed in the liquid. What is the apparent weight of the body in the liquid?

Buoyant force exerted by the liquid = 2.4 kg
Mass of the body when immersed in liquid, m = 6.4 kg 

Therefore,

Apparent weight of the body in the liquid is given by, = 6.4 –2.4 = 4 kg. 
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A cork is floating in water. What is the apparent weight of the cork?

Apparent weight = weight of cork - weight of displaced liquid. 

When the cork is floating in the liquid, the weight of the cork is equal to the weight of the liquid displaced. 

So, the apparent weight = 0
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When the floating bodies are in unstable equilibrium?

For floating bodies, the centre of buoyancy lies below the centre of gravity. Hence, they are in unstable equilibrium. 
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What the distance between meta centre and centre of buoyancy called?


The distance between meta centre and centre of buoyancy is called meta-centre height.

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What is the direction in which the buoyant force acts?

Bouyant force acts in the upward direction. That is in a direction opposite to the direction of gravity.
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