﻿ Two limbs of hydraulic lift have area of cross-section 5 cm2 and 100 cm2. To lift the weight of 24 kg placed on 5 cm2 cross-section, what force must be applied on the piston of cross-section 100 cm2? from Physics Mechanical Properties of Fluids Class 11 Manipur Board

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Two limbs of hydraulic lift have area of cross-section 5 cm2 and 100 cm2. To lift the weight of 24 kg placed on 5 cm2 cross-section, what force must be applied on the piston of cross-section 100 cm2?

Given, two hydraulic lifts.

Area of cross-section of first limb = 5 cm2

Area of cross section of second limb = 100 cm

Weight of the load = 24

Area of cross-section on which the load is kept = 5 cm2

Now, using Pascal's law, we have

Here, a= 5 cm2 , F= 235 N
a2 = 100 cm2

So, force F2, is the force applied on a piston of cross-sectional area 100 cm2

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