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When large number of small droplets coalesces to from a single drop, it warms up. Explain why.


The surface area of the free surface decreases, when large number of small droplets coalesces to from a single drop. This results in decrease in the potential energy in the surface film which is converted into heat and increases the temperature of the drop. 
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Work has to be done to increase the area of free surface of liquid. Explain it in accordance with the law of conservation of energy.

No net force is experienced by the molecules in the bulk of liquid and are free to move within. But, a net inward pull is experienced by the molecules in the surface film. When the area of the free surface is increased, the molecules from bulk move to surface film against the inward pull and hence work has to be done to increase the area of free surface. 
This work is stored in the form of potential energy. Therefore, work done to increase the area of the surface of liquid is in accordance with the law of conservation of energy. 
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Derive an expression for excess of pressure inside a soap bubble.

Consider a soap bubble of radius R and surface tension T. There are two free surfaces of soap bubble. Due to surface tension the molecules on the surface film experience the net force in inward direction normal to the surface. Therefore there is more pressure inside than outside. Let pi be pressure inside the liquid drop and po the pressure outside the drop. Therefore excess of pressure inside the liquid drop is,

p =p1–Po



Consider a soap bubble of radius R and surface tension T. There are t

Due to excess of pressure inside the liquid drop the free surface of the drop will experience the net force in outward direction due to which the drop expands. Let the free surface be displaced by dR under isothermal conditions.

Therefore excess of pressure does the work in displacing the surface and that work will be stored in the form of potential energy.

The work done by excess of pressure in displacing the surface is,

dW= Force x displacement 
     = (excess of pressure x Surface area) x displacement of surfce

    italic equals p italic cross times italic 4 pi R to the power of italic 2 cross times dR space space space space space space space space space space space space space space space space space space space space space space space..... left parenthesis 1 right parenthesis
Increase in the potential energy
dU = surface tension x increase in area of the free surface


equals space straight T space open square brackets 2 open parentheses 4 straight pi open parentheses straight R plus dR squared close parentheses minus 4 πR squared close parentheses close square brackets
equals space straight T space open square brackets 2 open curly brackets 4 straight pi open parentheses 2 RdR close parentheses close curly brackets close square brackets space space space space space space space space space space space space space space space space space space space space space space space space space.... left parenthesis 2 right parenthesis

From (1) and (2)

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What should be the ratio of cohesive force between liquid molecules and the adhesive force between liquid molecules and the tube molecules so that the shape of meniscus is: (i) concave (ii) convex? 

When we dip the capillary tube in liquid, at the contact two types of forces are acting on liquid molecule as shown:


When we dip the capillary tube in liquid, at the contact two types of

(i) Adhesive force by molecules of tube perpendicular to the surface of tube.

(ii) Cohesive force by liquid molecules at angle 45°

  
space space space space If space space space space space italic space italic space italic space italic space italic space italic integral subscript a italic greater than italic integral subscript c s i n italic space italic 45 italic degree italic space italic equals fraction numerator f subscript c over denominator square root of italic 2 end fraction
The resultant force or liquid molecule is outside the tube and meniscus is concave, and 


space If space space space space space italic space italic space italic space italic space italic space italic integral subscript a italic greater than italic integral subscript c s i n italic space italic 45 italic degree italic space italic equals fraction numerator f subscript c over denominator square root of italic 2 end fraction   

then meniscus is convex.

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Name two applications of surface tension in our daily life.

Applications of Surface tension in daily life are:

(i) The surface tension of antiseptic ointments is low which make them to spread over the wound.

(ii) Adding detergent in water decreases the surface tension of water and enhances the cleaning action of water and detergent both.

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