Derive an expression for the radius of rope used in a crane to lift the mass M kg. The elastic limit of the material of rope is σ N/m2, and safety factor of crane is K.
Given mass = M kg
Elastic limit of the material = σ N/m2
Safety factor for crane = K
The design of the rope is such that it should tolerate a load of KM kg.
Let r be the radius of rope required to be used in the crane.
So, using the formula,